# Gross Salary Codechef Solution

In a company an emplopyee is paid as under: If his basic salary is less than Rs. 1500, then HRA = 10% of base salary and DA = 90% of basic salary.

If his salary is either equal to or above Rs. 1500, then HRA = Rs. 500 and DA = 98% of basic salary. If the Employee’s salary is input, write a program to find his gross salary.

NOTE: Gross Salary = Basic Salary + HRA + DA

## Input

The first line contains an integer T, total number of testcases. Then follow T lines, each line contains an integer salary.

## Output

For each test case, output the gross salary of the employee in a new line. Your answer will be considered correct if the absolute error is less than 10^-2.

## Constraints

• 1 ≤ T ≤ 1000
• 1 ≤ salary ≤ 100000

## Example

Sample Input

```3
1203
10042
1312```

Sample Output

```2406.00
20383.16
2624
```

## Gross Salary – CodeChef Solution in Python

```T = int(input())
for i in range(T):
n = int(input())
if n < 1500:
salary = n + (90*n/100) + (10*n/100)
print(salary)
else:
salary = n + (98*n/100) + 500
print(salary)```

## Gross Salary – CodeChef Solution in CPP

```#include <stdio.h>

int main(){
int a;
scanf("%d",&a);
while(a--){
long b;
float d;
scanf("%li",&b);
if(b<1500)
printf("%g\n",b+0.1*b+0.9*b);
else{
printf("%g\n",b+500+b*0.98);
}
}
}```

## Gross Salary – CodeChef Solution in JAVA

```import java.util.*;
class CodeChef
{
public static void main(String args[]){
Scanner s = new Scanner(System.in);
int n = s.nextInt();
for(int i=0;i<n;i++)
{
int a = s.nextInt();
float sal;
if(a<1500)
{
sal = (float)(a + (0.10*a)+(0.90*a));
}
else
{
sal = (float) (a+500+(0.98*a));
}
System.out.println(sal);
}

}
}```

Disclaimer: The above Problem (Gross Salary) is generated by CodeChef but the solution is provided by Chase2learn.This tutorial is only for Educational and Learning purpose.