Java Exception Handling – Hacker Rank Solution

Java Exception Handling - Hacker Rank Solution
Java Exception Handling – Hacker Rank Solution

Objective

You are required to compute the power of a number by implementing a calculator. Create a class MyCalculator which consists of a single method long power(int, int). This method takes two integers, n and p, as parameters and finds . 

Problem Statement: Click Here



Java Exception Handling – Hacker Rank Solution

import java.util.*;
import java.util.Scanner;

class MyCalculator {
    long power(int n, int p) throws Exception {
        if (n < 0 || p < 0) {
            throw new Exception("n or p should not be negative.");
        } else if (n == 0 && p == 0) {
            throw new Exception("n and p should not be zero.");
        } else {
            return (long) Math.pow(n, p);
        }
    }
}

class Solution {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            MyCalculator my_calculator = new MyCalculator();
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}

Disclaimer: The above Problem (Java Exception Handling ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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